This is geneticly the result of the done breeding:
black cock E/eb S/s+ X white hen eb/eb s+/- c/c
resulting in:
12,5% black cocks E/eb C+/c S/s+
12,5% black cocks E/eb C+/c s+/s+
12,5% black hens E/eb C+/c S/-
12,5% black hens E/eb C+/c s+/-
12,5% perniciato argento hens eb/eb C+/c S/-
12,5% perniciato oro hens eb/eb C+/c s+/-
12,5% perniciato argento/oro cocks eb/eb C+/c S/s+
12,5% perniciato oro cocks eb/eb C+/c s+/s+
E = black
eb= perniciato
C+= NOT rezessiv white
c = rezessiv white
S = argento
s+= oro
alleles with a Capital (E or S) need only one to see in fenotipo
alleles with NO capital (c or s+)need two to see in fenotipo.
As Tunde said is it impossible that a chick is blue in this combination because blue is "Dominant gen that acts Intermidiar" meaning:
bl+/bl+ = no blue = black
Bl/bl+ = blue
Bl/Bl = splash
So blue delute black (not red).
Ciao Danny
[Modificato da Danny_57 23/11/2008 13:08]